12x^2+3x=60

Solution for 12x^2+3x=60 equation:

12x^2+3x=60

We move all terms to the left:

12x^2+3x-(60)=0

a = 12; b = 3; c = -60;
Δ = b2-4ac
Δ = 32-4·12·(-60)
Δ = 2889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2889}=\sqrt{9*321}=\sqrt{9}*\sqrt{321}=3\sqrt{321}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3\sqrt{321}}{2*12}=\frac{-3-3\sqrt{321}}{24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3\sqrt{321}}{2*12}=\frac{-3+3\sqrt{321}}{24}
$